\tan \theta=1\frac{8 \sin \theta+5 \cos \theta}{\sin ^{3} \theta-2 \co – InterviewSolution

1.	\tan \theta=1\frac{8 \sin \theta+5 \cos \theta}{\sin ^{3} \theta-2 \cos ^{3} \theta+7 \cos \theta} = ?
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