1.

Tan power 2 thetha sin power 2 thetha =tan power 2 thetha minus sin power 2 thetha

Answer»

To PROVE:- tan²Θ Sin²Θ = tan²Θ - Sin²Θ

LHS: tan²Θ Sin²Θ = Sin²Θ (1 - Cos²Θ) / Cos²Θ

= (Sin²Θ - Sin²Θ Cos²Θ) / Cos²Θ

= Sin²Θ / Cos²Θ - Sin²Θ Cos²Θ / Cos²Θ

= tan²Θ - Sin²Θ = RHS

Hence proved

Formulas - tanΘ = SinΘ/CosΘ, Sin²Θ = 1 - Cos²Θ

Hope I HELPED



Discussion

No Comment Found

Related InterviewSolutions