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Tan power 2 thetha sin power 2 thetha =tan power 2 thetha minus sin power 2 thetha |
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Answer» To PROVE:- tan²Θ Sin²Θ = tan²Θ - Sin²Θ LHS: tan²Θ Sin²Θ = Sin²Θ (1 - Cos²Θ) / Cos²Θ = (Sin²Θ - Sin²Θ Cos²Θ) / Cos²Θ = Sin²Θ / Cos²Θ - Sin²Θ Cos²Θ / Cos²Θ = tan²Θ - Sin²Θ = RHS Hence proved Formulas - tanΘ = SinΘ/CosΘ, Sin²Θ = 1 - Cos²Θ Hope I HELPED |
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