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tan O + tan 20 + tan 0. taअथवा/ एन |
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Answer» Tan3θ = tan (2θ+θ) = tan2θ + tanθ / 1- tanθtan2θ given tanθ +tan2θ + tanθtan2θ = 1 tanθ + tan2θ = 1- tanθtan2θ tanθ + tan2θ / 1 - tanθtan2θ = 1 tan3θ = 1 tan3θ = tan 45 3θ = 45 θ = 45/3 = 15 or π/12 |
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