1.

tan O + tan 20 + tan 0. taअथवा/ एन

Answer»

Tan3θ = tan (2θ+θ) = tan2θ + tanθ / 1- tanθtan2θ

given tanθ +tan2θ + tanθtan2θ = 1

tanθ + tan2θ = 1- tanθtan2θ

tanθ + tan2θ / 1 - tanθtan2θ = 1

tan3θ = 1

tan3θ = tan 45

3θ = 45

θ = 45/3 = 15 or π/12



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