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tan A+tan BShow thattan A +cotB= tanA . tan BB |
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Answer» There must be an error in the question so this would be the answer (tan A+tan B) / (cot A+cot B)⇒(tan A+tan B) / (1/tan A+1/tan B)⇒(tan A +tan B) / (tan A+tan B / tan A·tan B)⇒(tan A+tan B) / (tan A·tan B / tan A+tan B)⇒tan A·tan Bhence proved |
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