tan A+ sec A - 1/ tan A - sec A + 1= 1+sinA/ cos A.

1.	tan A+ sec A - 1/ tan A - sec A + 1= 1+sinA/ cos A.
Answer» Using identity sec^2A-tan^2A=1 we gettanA+secA-(sec^2A-tan^2A)÷tanA-secA+1 So tanA + sec A -(secA+tanA)(secA-tanA)÷tanA-secA+1=( tan A + secA)(1-secA+tanA)÷tanA -sec A +1On cancelling the terms we get tan A + sec A = sinA/cos A +1/cosA= sinA+1/cosA

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