Tan 4 A = cot(A-20) find 3A

1.	Tan 4 A = cot(A-20) find 3A
Answer» GIVEN : Tan 4A = Cot(A - 20) Convert Tan 4A in the FORM of Cot using IDENTITIES. Cot ( 90 - 4A ) = Cot ( A - 20 ) [ Tan Ø = Cot ( 90 - Ø ) Cancel Cot on the both sides. Cot ( 90 - 4A) = Cot ( A - 20 ) 90 - 4A = A - 20 90 + 20 = A + 5A 110 = 5A A = 110/5 A = 22 If A = 22 Then, 3A = 3(22) = 66 Therefore, the VALUE of 3A is 66.

Answer»

GIVEN :

Tan 4A = Cot(A - 20)

Convert Tan 4A in the FORM of Cot using IDENTITIES.

Cot ( 90 - 4A ) = Cot ( A - 20 ) [ Tan Ø = Cot ( 90 - Ø )

Cancel Cot on the both sides.

Cot ( 90 - 4A) = Cot ( A - 20 )

90 - 4A = A - 20

90 + 20 = A + 5A

110 = 5A

A = 110/5

A = 22

If A = 22

Then,

3A = 3(22) = 66

Therefore, the VALUE of 3A is 66.

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Tan 4 A = cot(A-20) find 3A

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