1.

∫ tan-1x dx is equal to(a) (x+1)tan-1x-x+C (b) x tan-1x-x+C(c) x-x tan-1 x+C (d) x-(x+1)tan-1x+C

Answer» tan-1x dx is equal to(a) (x+1)tan-1x-x+C (b) x tan-1x-x+C(c) x-x tan-1 x+C (d) x-(x+1)tan-1x+C


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