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tan-1 x + tanı y + tan-1 z-πx+y+z = xyz(ii)'AFE3.8陋(Rne R, |
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Answer» tan-1x+tan-1y+tan-1z=π -: tan-1(x+y/1-xy)+z=π. [tan-1x+tan-1y =(x+y/1-xy)] -: (x+y/1-xy)+z=tanπ -: (x+y/1-xy)+z=0 -: (x+y/1-xy)=-z -: x+y=-z(1-xy) -: x+y=-z+xyz Hence, x+y+z=xyz |
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