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\tan ^{-1}\left(\frac{1}{2}\right)+\tan ^{-1}\left(\frac{1}{5}\right)+\tan ^{-1}\left(\frac{1}{8}\right)=\frac{\pi}{4} |
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Answer» tan^(-1)((1/2+1/5)/(1-1/10))+tan^(-1)(1/8)=tan^(-1)(7/10 / 9/10)+tan^(-1)(1/8)=tan^(-1)(7/9)+tan^(-1)(1/8)=tan^(-1)((7/9+1/8)/(1-7/72))=tan^(-1)(65/65)=tan^(-1)(1)=pie/4 please answer rest of the questions |
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