1.

\(tan^{-1} \left(\cfrac{cos\left(\frac{15\pi}{4}\right) - 1}{sin\frac\pi4}\right)\) equal to(1) \(-\frac\pi4\)(2) \(-\frac{4\pi}9\)(3) \(-\frac\pi8\)(4) \(-\frac{3\pi}8\)

Answer»

Correct option is (3) \(-\frac\pi8\) 

\(tan^{-1} = \left(\frac{\frac1{\sqrt2}- 1}{\frac1{\sqrt2}}\right)\)

\(=tan^{-1}(1 - \sqrt2)\)

\(= - tan^{-1}(\sqrt 2 - 1)\)

\(= -\frac\pi8\)



Discussion

No Comment Found

Related InterviewSolutions