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\(tan^{-1} \left(\cfrac{cos\left(\frac{15\pi}{4}\right) - 1}{sin\frac\pi4}\right)\) equal to(1) \(-\frac\pi4\)(2) \(-\frac{4\pi}9\)(3) \(-\frac\pi8\)(4) \(-\frac{3\pi}8\) |
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Answer» Correct option is (3) \(-\frac\pi8\) \(tan^{-1} = \left(\frac{\frac1{\sqrt2}- 1}{\frac1{\sqrt2}}\right)\) \(=tan^{-1}(1 - \sqrt2)\) \(= - tan^{-1}(\sqrt 2 - 1)\) \(= -\frac\pi8\) |
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