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`tan^(- 1)(a/x)+tan^(- 1)(b/x)=pi/2` then `x=`A. `sqrt(ab)`B. `sqrt(2ab)`C. 2abD. ab |
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Answer» We have `tan^(-1_(a)/(x)+tan^(-1)(b)/(x))=(pi)/(2)` `rarrtan^(-1)((a)/(x)+(b)/(x)-(ab)/(x^(2)))=(pi)/(2)rarr1-(ab)/(x^(2))=0rarrx=sqrt(ab)` |
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