1.

Tabulate the apparent weight of person moving in a lift when lift is (i) moving upwards (ii) moving downwards (iii) at rest (iv) falling down freely

Answer»
Case 1 : Lift is moving upward with an acceleration 'a'Case 2 : Lift is moving downward with an acceleration 'a'Case 3 : Lift is at restCase 4 :Lift is falling down freely
R - w = Fnet = ma
R = w + ma
R = mg +ma
R = m (g + a)
W -R = Fnet = ma
R = W - ma
R = mg - ma
R = m (g - a)
Here, the acceleration is zero
a = 0
R = W
R = mg
Here, the acceleration is equal to g
a = g
R = m(g - g)
R >WR <WR = WR = 0
Apparent weight is greater then the actual weight.Apparent weight is lesser than the actual weight.Apparent weight is equal to the actual weight.Apparent weight is equal to zero.



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