1.

Table below given analogy between translational and rotational motions. Match the following.Linear motionRelation motionvelocityAngular momentummass1/2 τω2\(\frac{1}{2}\) mv2τ = \(\frac{dL}{dt}\)a = \(\frac{dv}{dt}\)Moment of inertiaF = \(\frac{dp}{dt}\)1/2 lω2F = \(\frac{dl}{dt}\)Torque a =\(\frac{dω}{c^"}\)

Answer»
Linear motionRelation motion
velocityAngular momentum
massMomentum of inertia
ForceTorque
\(\frac{1}{2}\) mv2 1/2 τω2
a = \(\frac{dv}{dt}\)

  a =\(\frac{dω}{c^"}\)

F = \(\frac{dp}{dt}\)

 τ = \(\frac{dL}{dt}\) 


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