1.

T/V) B+ <z(fimz—_vmopv[vi ue) -y uisपा! +प्य्त (71

Answer»

LHS:sin A.tan(A/2) + 2cosA(using cos 2A = 1-tan^2 A/1+tan^2 Asin 2A = 2tan A/1+tan^2 A)

=(2tan A/2)/(1+tan^2 A/2). tan A/2 + 2(1-tan^2 A/2)/(1+tan^2 A/2)

= (2tan^2 A/2 + 2 - 2tan^2 A/2)/(1 + tan^2 A/2)

= 2/(1 + tan^2 A/2)

= RHS

Hence proved



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