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Symmetric form of the line through (-2,0) having slope '-1/root 3' is

Answer»

ave to find the symmetric form of the LINE through (-2,0) having slope -1/√3.

solution : Symmetric form of line is REPRESENTED by x/a + y/b = 1, where a is x - intercept and b is y - intercept and a ≠ 0 , b ≠ 0.

FIRST find the equation of line USING (y - y₁) = m(x - x₁) where m is slope of line and (x₁ , y₁) is a point on the line.

here (x₁ , y₁) = (-2,0) and m = -1/√3

so, (y - 0) = -1/√3(x + 2)

⇒√3y + x + 2 = 0

⇒x + √3y = -2

⇒x/-2 + √3y/-2 = 1

⇒x/(-2) + y/(-2/√3) = 1

Therefore symmetric form of the line is x/(-2) + y/(-2/√3) = 1.



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