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Surface tension of water is 73 dyne `cm^(-1)` at `20^(@)C`. If surface area is increased by `0.10" m"^(2)`, work done will beA. 73 ergsB. 730 ergsC. 7300 ergsD. 73000 ergs |
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Answer» Correct Answer - D Work done=Surface tension xxIncrease in surface area `=73" dyne "cm^(-1)xx0.1" m"^(2)` `=73" dynwe "cm^(-1)xx0.1xx10^(4)"ergs"` `=7.3xx10^(4)" dyne " cm=7.3xx10^(4)" ergs"` |
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