1.

Surface tension of water is 73 dyne `cm^(-1)` at `20^(@)C`. If surface area is increased by `0.10" m"^(2)`, work done will beA. 73 ergsB. 730 ergsC. 7300 ergsD. 73000 ergs

Answer» Correct Answer - D
Work done=Surface tension xxIncrease in surface area
`=73" dyne "cm^(-1)xx0.1" m"^(2)`
`=73" dynwe "cm^(-1)xx0.1xx10^(4)"ergs"`
`=7.3xx10^(4)" dyne " cm=7.3xx10^(4)" ergs"`


Discussion

No Comment Found

Related InterviewSolutions