1.

Suppose x varies directly as y and inversely as z. If x=30 when y =40 and z=80, find x when y= 24 and z=40

Answer»

SOLUTION

GIVEN

  • Suppose x varies directly as y and inversely as z.

  • x=30 when y =40 and z=80,

TO DETERMINE

The value of x when y = 24 and z=40

EVALUATION

Here it is given that x varies directly as y and inversely as z

\displaystyle \sf{\implies \: x \propto \:  \frac{y}{z} }

\displaystyle \sf{\implies \: x   = \:  \frac{ky}{z} } \:  \:  \:  -  -  -  - (1)

Where k is a non ZERO real number

Now x = 30 , y = 40 , z = 80 gives

\displaystyle \sf{\implies \: 30  = \:  \frac{40k}{80} } \:  \:  \:

\displaystyle \sf{\implies \:40k = 2400 } \:  \:  \:

\displaystyle \sf{\implies \:k =60 } \:  \:  \:

Equation 1 gives

\displaystyle \sf{ x   = \:  \frac{60y}{z} } \:  \:  \:  -  -  -  - (2)

Now y = 24 , z = 40 gives

\displaystyle \sf{\implies \: x   = \:  \frac{60 \times 24}{40} } \:  \:  \:

\displaystyle \sf{\implies \: x   = \:  36}

FINAL ANSWER

Hence the required value of x = 36

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