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Suppose that one in 200 long-distance telephone calls is misdirected. What is the probability that at least one in five attempted telephone calls reaches the wrong number? (Assume independence of attempts.) |
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Answer» GIVEN : ONE in 200 long-distance telephone calls is misdirected. To find : probability that at LEAST one in five attempted telephone calls reaches the wrong number Solution: one in 200 long-distance telephone calls is misdirected => probability of call misdirecting p = 1/200 Probability of call not Misdirecting = 1 - 1/200 = 199/200 Number of Calls = 5 P(x) = ⁿCₓpˣqⁿ⁻ˣ n = 5 p = 1/200 q = 199/200 at least one in five attempted telephone calls reaches the wrong number = 1 - none of the call reaches the wrong number = 1 - P(0) = 1 - ⁵C₀(1/200)⁰(199/200)⁵⁻⁰ = 1 - (199/200)⁵ = 0.02475 HOPE IT HELPS YOU MARK ME AS BRAINLIEST |
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