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Suppose that `g(x)=1+sqrt(x) " and " f(g(x))=3+2sqrt(x)+x.` Then find the function `f(x)`. |
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Answer» `g(x)=1+sqrt(x) " and " f(g(x))=3+2sqrt(x)+x " " `(1) ` :. f(1+sqrt(x))=3+2sqrt(x)+x` Put `1+sqrt(x)=y " or " x=(x-y)^(2).` Then, `f(y)=3+2(y-1)+(y-1)^(2)=2+y^(2).` ` :. f(x)=2+x^(2)` |
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