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| 1. |
Suppose a series of `n` terms given by `S_(n)=t_(1)+t_(2)+t_(3)+`. . . .`+t_(n)` then `S_(n-1)=t_(1)+t_(2)+t_(3)+`. . . .`+t_(n-1),nge1` subtracting we get `S_(n)-S_(n-1)=t_(n),nge2` surther if we put `n=1` is the first sum then `S_(1)=t_(1)` thus w can write `t_(n)=S_(n)-S_(n-1),nge2` and `t_(1)=S_(1)` Q. The sum of `n` terms of a series is `a.2^(n)-b`. where a and b are constant then the series isA. A.PB. G.PC. A.G.PD. G.P from second term onwards |
| Answer» Correct Answer - D | |