Sumitra has rs.34 in 50 Paise and25paise coins . If the number of 25 P

1.	Sumitra has rs.34 in 50 Paise and25paise coins . If the number of 25 Paise coins is twice the number of 50Paise coins, how many coins of each kind dose she have?
Answer» ANSWER: The number of 50 Paise COIN = 34 The number of 25 Paise coin = 68 Step-by-step explanation: Let, The number of 50 Paise coin = x The number of 25 Paise coin = 2X Total amount = Rs 34 Rs. 1 = 100 Paise 34 × 100 3400 paise ★ Value of coin : 50 Paise coin = x 50x 25 Paise coin = 2x 2x × 25 50x ★ According to the question : ⇒ 50x + 50x = 3400 ⇒ 100x = 3400 ⇒ x = 3400 / 100 ⇒ x = 34 ★ Value of 2x : ⇒ 2 (34) ⇒ 2 × 34 ⇒ 68 Therefore, The number of 50 Paise coin = 34 The number of 25 Paise coin = 68

Sumitra has rs.34 in 50 Paise and25paise coins . If the number of 25 Paise coins is twice the number of 50Paise coins, how many coins of each kind dose she have?

Answer»

ANSWER:

The number of 50 Paise COIN = 34

The number of 25 Paise coin = 68

Step-by-step explanation:

Let,

The number of 50 Paise coin = x

The number of 25 Paise coin = 2X

Total amount = Rs 34

Rs. 1 = 100 Paise

34 × 100

3400 paise

★ Value of coin :

50 Paise coin = x

50x

25 Paise coin = 2x

2x × 25

50x

★ According to the question :

⇒ 50x + 50x = 3400

⇒ 100x = 3400

⇒ x = 3400 / 100

⇒ x = 34

★ Value of 2x :

⇒ 2 (34)

⇒ 2 × 34

⇒ 68

Therefore,

The number of 50 Paise coin = 34

The number of 25 Paise coin = 68

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