Sum of two numbers is 98.If one number is 16 more than the other, the

1.	Sum of two numbers is 98.If one number is 16 more than the other, the number are
Answer» $\huge\tt{\bold{\underline{\underline{<klux>QUESTION</klux>᎓}}}}$ SUM of two numbers is 98.If ONE number is 16 more than the other, the number are $\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$ ┏━━━━━━━━━━━━━━━━━━━━━━━┓ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ ✍️ Let the first number be 'x' Second number be x+16 According to the question:-- $= > x + x + 16 = 98$ $= > 2x + 16 = 98$ $= > 2x = 98 - 16$ $= > 2x = 82$ $= > x = 41$ $\bold{First\: number\: is\:{\red{ 41 }}}$ $\bold{second\: number\: =x+16=41+16={\blue{57}}}$ Therefore,The number are (41,57) $\bold{sum = 41 + 57 = 98}$ ┗━━━━━━━━━━━━━━━━━━━━━━━┛