sum of two digits of a 2 digit number is 12. if the digits are reverse

1.	sum of two digits of a 2 digit number is 12. if the digits are reversed, the new number, so formed increase by 36. find the number
Answer» Answer: Tens digit of NUMBER = x Ones digit of number = 12-x Original Number = 10x+12-x = 9x+12 REVERSED Number = 10(12-x)+x = 120-10x+x = 120-9x According to the question, 9x+12+36=120-9x 9x+48=120-9x 9x+9x=120-48 18x=72 x=72/18 x=4 Original Number = 9x+12 = 9(4)+12 = 36+12 = 48 is the number

sum of two digits of a 2 digit number is 12. if the digits are reversed, the new number, so formed increase by 36. find the number

Answer»

Answer: Tens digit of NUMBER = x

Ones digit of number = 12-x

Original Number = 10x+12-x

= 9x+12

REVERSED Number = 10(12-x)+x

= 120-10x+x

= 120-9x

According to the question,

9x+12+36=120-9x

9x+48=120-9x

9x+9x=120-48

18x=72

x=72/18

x=4

Original Number = 9x+12

= 9(4)+12

= 36+12

= 48 is the number

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sum of two digits of a 2 digit number is 12. if the digits are reversed, the new number, so formed increase by 36. find the number ​

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sum of two digits of a 2 digit number is 12. if the digits are reversed, the new number, so formed increase by 36. find the number