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Sum of three numbers in AP is 21 product of first and third number of the sequence is 45 what are the three numbers |
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Answer» Answer: 5,7,9 Step-by-step explanation: let let the NUMBERS be a+d,a,a-d a+d+a+a-d=21 3a=21 a=7 and (a+d)(a-d)=45 a²-d²=45 d²=4 d=±2 hence the numbers are 5,7,9 when d= 2 and 9,7,5 when d=-2. so in both the GIVEN cases the NUMBER are same. |
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