1.

Sum of three numbers in AP is 21 product of first and third number of the sequence is 45 what are the three numbers​

Answer»

Answer:

5,7,9

Step-by-step explanation:

let let the NUMBERS be a+d,a,a-d

a+d+a+a-d=21

3a=21

a=7

and (a+d)(a-d)=45

a²-d²=45

d²=4

d=±2

hence the numbers are 5,7,9 when d= 2 and 9,7,5 when d=-2. so in both the GIVEN cases the NUMBER are same.



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