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Sum of those integer between 1 to 500 which are multiple of 2 as well as 5 |
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Answer» As numbers which have factors only 2 and 5 are the multiples of 10 like 10,20,...50Hence hereina=10d=20-10=10al=500 that is the last termHencean=500hence500=a+(n-1)d500=10+(n-1)*10490=(n-1)*10n-1=49n=50Hencesum=n/2(a+l)=50/2(10+500)=25*510=12750 |
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