Sum of the natural number between 500 and 1000 which are divisible by

1.	Sum of the natural number between 500 and 1000 which are divisible by 105
Answer» Answer: Sum=3675 Step-by-step explanation: Number between 500 and 1000 which are divisible by 105 can be USED to form a series of Arithmetic Progression like 525,630.......945. Now, taking FIRST term = 525 and common difference = 105, nth term = 945= 525+(n-1)105 On solving the above EQUATION, we get n=5. Now Sum of 5 terms of an A.P. = (n/2)(first term+last term) =(5/2)(525+945) =3675 And that's the explanation... Hope it Helped all...:-)

Sum of the natural number between 500 and 1000 which are divisible by 105

Answer»

Answer: Sum=3675

Step-by-step explanation:

Number between 500 and 1000 which are divisible by 105 can be USED to form a series of Arithmetic Progression like

525,630.......945.

Now, taking FIRST term = 525 and common difference = 105,

nth term = 945= 525+(n-1)105

On solving the above EQUATION, we get n=5.

Now Sum of 5 terms of an A.P. =

(n/2)(first term+last term)

=(5/2)(525+945)

=3675

And that's the explanation... Hope it Helped all...:-)

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Sum of the natural number between 500 and 1000 which are divisible by 105​

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Sum of the natural number between 500 and 1000 which are divisible by 105