1.

Sum of the LCM and HCF of two numbers is 2790 and their difference is2610. If one number is 270 then find the other.

Answer»

Answer:

LET a and B be the LCM and HCF respectively.

a + b = 2196 and

a - b = 2172

We get 2a = 4368, a= 2184

b = 2196 - 2184 = 12,

So we have the HCF as 12 and LCM as 2184.

Give that difference of the number is 12.

Let one of the number is n, other number will be n+12.

12 is the common factor, so we can write n as 12m.

So the two numbers are 12m and 12(m+1).

LCM = product of the 2 numbers/ HCF

ie 2184 = 12m x 12(m+1)/12

2184 = 12m^2 + 12m

ie m^2 + m - 182

Solving we get m as 13.

So the numbers are 12X(13) and 12x(13+1)

ie 156 and 168.

Sum of numbers = 156 + 168 = 324

Step-by-step explanation:

please make me as BRANIEST


Discussion

No Comment Found

Related InterviewSolutions