sum of the digits of a two-digit number is 8. If the digits are revers

1.	sum of the digits of a two-digit number is 8. If the digits are reversed, the new number increases by 18.TheFind the number.
Answer» x + y = 8 {equation 1} The value of xy is 10x + y The value of yx is 10y + x 10y + x = 10x + y + 18 9y - 9x = 18 9(y - x) = 18 y - x = 2 From equation 1: y = 8-x 8 - x - x = 2 8 - 2x = 2 -2x = -6 x = 3 y - x = 2 y - 3 = 2 y = 5 Originalnumber xy = 35

sum of the digits of a two-digit number is 8. If the digits are reversed, the new number increases by 18.TheFind the number.

Answer»

x + y = 8 {equation 1}

The value of xy is 10x + y

The value of yx is 10y + x

10y + x = 10x + y + 18

9y - 9x = 18

9(y - x) = 18

y - x = 2

From equation 1: y = 8-x

8 - x - x = 2

8 - 2x = 2

-2x = -6

x = 3

y - x = 2

y - 3 = 2

y = 5

Originalnumber xy = 35