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Sum of the digits of a number of two digits is 8e interchange the digits, we see that thebetween the numbers is 18. Find theoriginal number. |
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Answer» Ans :- Let us assume the digits of a number as 'x' and 'y'. Since it is a 2 digit number, we have one's place and ten's place. ( i.e., The place value of one digit is multiple of 10 and the place value of other digit is one.) I assume you know the difference between place value and face value. Now going to the problem, Sum of two digits is 8. => x +y=8→A Diff between number and its reverse: => (10x+y)-(10y+x)=18 =>9x-9y=18 => x-y=(18/9)=2→B Solving A and B x+y=8 x-y=2 =>2x=10=>x=5. Hence y = 3. Hence the required number is53 answer is 35 |
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