1.

Sum of first 9 terms of an ap is 279. find its 10th term of d = 8​

Answer»

Answer:

287.

Step-by-step EXPLANATION:

GIVEN,

a_{9} = 279 \\ \\ a + (9 - 1)(8) = 279 \\ \\ a + 8 \times 8 = 279 \\ \\ a = 279 - 64 \\ \\ \bf a = 215

10TH TERM of the AP

a_{10} = a + (n - 1)d \\ \\ a_{10} = 215 + (10 - 1)(8) \\ \\ a_{10} = 215 + 9 \times 8 \\ \\ a_{10} = 215 + 72 \\ \\ \bf a_{10} = 287


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