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Sum of distances fromA(3,4) to x axis from B(3,2)to y axis is |
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Answer» ✿distance b/w AB =√ (x2-x1)^2 + (y2-y1)^2 = √(3-3)^2 + (2-3)^2 = ✓1 ༎ຶ‿༎ຶ༎ຶ‿༎ຶ༎ຶ‿༎ຶ ✷so the distance b/w two pts AB is √1 |
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