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Sum of A's and B's age 6 years ago is 88. A's age 18 years ago is equal to B's age 6 years ago. Find the age of A two years hence.1. 58 years2. 52 years3. 56 years4. 42 years |
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Answer» Correct Answer - Option 1 : 58 years Given: Age (A + B), 6 years ago = 88 A's age 18 years ago = B's age 6 years ago Calculation: Let the present age of A be 'x' years and age of B be 'y' years (x - 6) + (y - 6) = 88 ⇒ x + y = 100 ---- (i) A's age 18 years ago = B's age 6 years ago x - 18 = y - 6 ⇒ x - y = 12 ---- (ii) Adding equation i and ii 2x = 112 or x = 56 Present age of A = x = 56 years ∴ The age of A two years hence = 56 + 2 = 58 years |
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