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sum of 5th term and 9th term of AP is 40 and the sum of the 14th term is 64 find the sum it first 20 term |
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Answer» Answer: Step-by-step explanation: Let a be the first TERM and d be the common difference of the AP. Then, A/Q (a + 4d) + ( a + 8d) = 40 a + 6d = 20 ......(i) and, (14/2)(2a + 13d) = 64 2a + 13d = 64/7 ........(ii) By solving equation (i) and (ii) , we get a = 236/7 and d = -16/7 Therefore, SUM of first 20 terms are (20/2)(2*(236/6) + 19(-16/7)) 240 |
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