1.

Sum of 4 terms in AP is 28 and the product of 1 and 4 term to product of 2 and 3 is 5:6 find the no

Answer»

Step-by-step EXPLANATION:

LET the for Numbers be (a-3d), (a-d), (a+d) and (a+3d),

then

according to the question, we have

(a-3d)+(a-d)+(a+d)+(a+3d)=28,

then

4a=28,

then

a=7,

ALSO

(a-3d)(a+3d)/(a-d)(a+d) = 5/6,

6(a²-9d²)=5(a²-d²) ,

6a²-54d²=5a²-5d²,

then

6a²-5a²=-5d²+54d²,

then

6a²-5a²=-5d²+54d²,

a²=49d²,

7²=49d²,

49=49d²,

then

d²=1,

hence

d=1,

therefore

1st number=(7-3×1)=7-3=4,

2nd number=(7-1)=6,

3rd number=(7+1)=8,

4th number=(7+3×1)=7+3=10


Discussion

No Comment Found

Related InterviewSolutions