Sulphurous acid (H2SO3) has Ka1=1.7×10−2 and Ka2=6.4×10−8. The p – InterviewSolution

1.	Sulphurous acid (H2SO3) has Ka1=1.7×10−2 and Ka2=6.4×10−8. The pH of 0.588 MH2SO3 is ______ (Round off to the Nearest Integer).
Answer» Sulphurous acid $(H_{2} S O_{3})$ has $K_{a 1} = 1.7 \times 10^{- 2}$ and $K a 2 = 6.4 \times 10^{- 8}$ . The pH of $0.588 M H_{2} S O_{3}$ is ______ (Round off to the Nearest Integer).

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