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Successive ionization potential of an element x are I.P.1=520Kj/mol, I.P.2=7298KJ/mol I. P.3=10815kj/mol What is the formula of its chloride and oxide??

Answer» Successive ionization potential of an element x are I.P.1=520Kj/mol, I.P.2=7298KJ/mol I. P.3=10815kj/mol What is the formula of its chloride and oxide??


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