Subtract the sum of 3 x minus 4 y + z and 1 - 2 x + y from the sum of

1.	Subtract the sum of 3 x minus 4 y + z and 1 - 2 x + y from the sum of 3 y + z + 6 and x - 2y + 3
Answer» $\huge\tt{\bold{\underline{\underline{Question᎓}}}}$ subtract the sum of 3 X minus 4 y + z and 1 - 2 x + y from the sum of 3 y + z + 6 and x - 2y + 3 $\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$ ┏━━━━━━━━━━━━━━━━━━━━━━━┓ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ ✍️ $= > 3x - 4y + z + 1 - 2x + y$ $= 3x - 2x - 4y + y + z + 1$ $\bold{= x - 3y + z + 1.......(1)}$ $= > 3y + z + 6 + x - 2y + 3$ $= x + 3y - 2y + z + 9$ $\bold{= x + y + z + 9.......(2)}$ Now,subtracting equation (1) from equation (2) $= > x + y + z + 9 - (x - 3y + z + 1)$ $= x + y + z + 9 - x + 3y - z - 1$ =>Here,when we open BRACKET -x and -z will come which will being cancelled by EXISTING +ve x and z. $\bold{= > 4y + 8 = }{\bold{\red{4(y + 2)}}}$ ┗━━━━━━━━━━━━━━━━━━━━━━━┛