Substitute method:5x+3y=35 2x+4y=28

1.	Substitute method:5x+3y=35 2x+4y=28
Answer» ong>Step-by-step explanation: ELIMINATION METHOD :- MULTIPLY 1ST equation by 2 and 2nd equation by 5 We GET 10x+6y=70 10x+20y=140 by solving we get Y=5 and X=4 Now BY SUBSTITUTION METHOD:-- Put x =35-3y/5 from 1st equation in 2nd equation we get 1/5(70-6y )+4y=28 by solving we get X=4 and Y=5 Was this answer helpful

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ong>Step-by-step explanation:

ELIMINATION METHOD :- MULTIPLY 1ST equation by 2 and 2nd equation by 5 We GET

10x+6y=70

10x+20y=140 by solving we get

Y=5 and X=4

Now BY SUBSTITUTION METHOD:--

Put x =35-3y/5 from 1st equation in 2nd equation

we get

1/5(70-6y )+4y=28

by solving we get

X=4 and Y=5

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Substitute method:5x+3y=35 2x+4y=28

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