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す1f可でー(i) (98)3(ii) (103)3(iii) (999)3 |
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Answer» Use:(a+b)^3=a^3+b^3+3(a)(b)(a+b)(a-b)^3=a^3-b^3-3(a)(b)(a-b) (98)^3=(100-2)^3=100^3 - 2^3 - 3(100)(2)(100-2)=1000000-8-58800=941192 similarly,(103)^3=(100+3)^3=100^3+3^3+3(100)(3)(100+3)=1000000+27+92700=1092727 (999)^3=(1000-1)^3=1000^3-1^3-3(1000)(1)(1000-1)=1000000000-1-2997000=997002999 |
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