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style="color:cyan;font-family:cursive;background:black;font size:25px;"> Q. A man is 4 times as old as his son . After 16 years he will. be only twice as old as his son . Find their present ages... [/tex]. ​

Answer»

Correct Question -

A man is 4 times as old as his son .

After 16 YEARS he will. be only twice as old as his son .

Find their present ages.

Solution -

Let the age of the son be x years .

So, the age of the man is 4X years .

After 16 years,

Age Of Son = x + 16 years .

Age of Man = 4x + 16 years.

Now , we have the FOLLOWING information given -

After 16 years he will. be only twice as old as his son .

Btw ,

4x + 16 = 2(x + 16 )

=> 4x + 16 = 2X + 32

=> 2x = 16

=> x = 8

So,

Age of Man = 4x = 32 .

Therefore Present Age of Son = x = 8 years.

Present Age of Man = 4x = 32 years.


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