Steam at 120∘C is continuously passed through a 50 -cm long rubber tube of inner and outer radii 1.0 cm and 1.2 cm. The room temperature is 30∘C. Calculate the rate of heat flow through the walls of the tube. Thermal conductivity of rubber = 0.15Js−1m−1∘C−1.

Steam at 120∘C is continuously passed through a 50 -cm long rubber t

1.	Steam at 120∘C is continuously passed through a 50 -cm long rubber tube of inner and outer radii 1.0 cm and 1.2 cm. The room temperature is 30∘C. Calculate the rate of heat flow through the walls of the tube. Thermal conductivity of rubber = 0.15Js−1m−1∘C−1.
Answer» Steam at $120^{\circ} C$ is continuously passed through a 50 -cm long rubber tube of inner and outer radii 1.0 cm and 1.2 cm. The room temperature is $30^{\circ} C$ . Calculate the rate of heat flow through the walls of the tube. Thermal conductivity of rubber = $0.15 J s^{- 1} m^{- 1 \circ} C^{- 1}$ .

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Steam at 120∘C is continuously passed through a 50 -cm long rubber tube of inner and outer radii 1.0 cm and 1.2 cm. The room temperature is 30∘C. Calculate the rate of heat flow through the walls of the tube. Thermal conductivity of rubber = 0.15Js−1m−1∘C−1.

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