1.

Steam at 120 bar has a specific volume of 0.01721 m3/kg, find the temperature, enthalpy and the internal energy.

Answer»

Pressure of steam, p = 120 bar

Specific volume, v = 0.01721 m3/kg 

(i) Temperature : 

First it is necessary to decide whether the steam is wet, dry saturated or superheated. At 120 bar, vg = 0.0143 m3/kg, which is less than the actual specific volume of 0.01721 m3/kg, and hence the steam is superheated. 

From the superheat tables at 120 bar, the specific volume is 0.01721 m3/kg at a temperature of 350°C.

(ii) Enthalpy :

From the steam tables the specific enthalpy at 120 bar, 350°C, 

h = 2847.7 kJ/kg.

(iii) Internal energy : 

To find internal energy, using the equation, 

u = h – pv

= 2847.7 – \(\cfrac{120\times10^5\times0.01721}{10^3}\) 

= 2641.18 kJ/kg.



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