Steam at 100∘C is passed into 1.1kg of water contained in a calorimeter of water equivalent 0.02kg at 15∘C till the temperature of the calorimeter and its contents reaches 80∘C. Considering the latent heat of steam =540calg−1 and specific heat capacity of water =4183Jkg−1K−1 or =1calkg−1K−1, calculate the mass of the steam condensed.

Steam at 100∘C is passed into 1.1kg of water contained in a calorime

1.	Steam at 100∘C is passed into 1.1kg of water contained in a calorimeter of water equivalent 0.02kg at 15∘C till the temperature of the calorimeter and its contents reaches 80∘C. Considering the latent heat of steam =540calg−1 and specific heat capacity of water =4183Jkg−1K−1 or =1calkg−1K−1, calculate the mass of the steam condensed.
Answer» Steam at $100^{\circ} C$ is passed into $1.1 k g$ of water contained in a calorimeter of water equivalent $0.02 k g$ at $15^{\circ} C$ till the temperature of the calorimeter and its contents reaches $80^{\circ} C$ . Considering the latent heat of steam $= 540 c a l g^{- 1}$ $and s$ pecific heat capacity of water $= 4183 J k g^{- 1} K^{- 1}$ ${or}$ $= 1 c a l k g^{- 1} K^{- 1}$ , calculate the mass of the steam condensed.