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Statement-1: For the reaction: `Ni^(2+)+2e^(-)rarrNi` and `Fe^(2+)+2e^(-)rarrFe` `rArr E_(Fe^(2+)|Fe)^(@)ltE_(Ni^(2+)|Ni)^(@)` and `E_("Red")^(@)gt0` `rArr` So Fe electrode is cathode and Ni electrode is anode. Statement-2: If `DeltaG^(@) lt0` and `E_("Cell")^(@)lt0`, then , cell is feasible.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-2C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer - D `E_(Ni^(+2)|Ni)^@=-0.24 " " E_(Fe^(+2)|Fe)^@=-0.44` `E_(Cell)^@=E_(Fe|Fe^(+2))^@+E_(Ni^(+2)|Ni)^@` =0.44-0.24=0.20 Fe electrode Anode, Ni electrode cathode `DeltaG lt 0 " " E_(Cell)gt0` For working of cell |
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