State the mole proportion of 12 g magnesium and 16 g sulphur. – InterviewSolution

1.	State the mole proportion of 12 g magnesium and 16 g sulphur.
Answer» 3:4 4:3 1:1 1:2 Solution :MOLE of 12 g MG = `(12)/(24)` = 0.5 Mole of 16g S = `(16)/(32)` = 0.5

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