Saved Bookmarks
| 1. |
State the explain the law of conservation of momentum of the system of particle. |
|
Answer» <P> Solution :Newton.s second law for the system of particle, `(dvecp)/(dt)=vecF_(EXT)`If the sum of external forces acting on the system of particles is zero then `(dvecp)/(dt)=0` `therefore dvecp=0, therefore vec(p_(1))=vecp_(2)` Means the linear momentum remains constant. (`vecp` = constant) Equation `vecp` = constant, it is equivalent to three scalar equation as following : `p_(x)=C_(1),p_(y)=C_(2),p_(3)=C_(3)` where `p_(x),p_(y),andp_(z)` are the components of linear momentum `vecp` for respective axis X, Y and Z-axis and `C_(1),C_(2)andC_(3)` are constant. ..When external total force acting on a system of particles is zero, then its total linear momentum remains constant... This is known as conservation of linear momentum. From `MvecA=vecF`, here `vecF` is total external force. If `vecF=0` then `MvecA=0` `therefore VECA=0` Means, ..when total external force on system is zero, the velocity of centre of mass remains constant... More over `vecA=(dvecv)/(dt)` then If `vecA=0` then `(dvecv)/(dt)=0` `therefore vecv` is constant. Means, total external force on the system is zero, the velocity of centre of mass remains constant. |
|