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State Faraday's secondlawof electrolysis |
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Answer» Solution :Second Law :When the samequantity of chargeis passedthroughthe solutionsof differentelectrolytes, the amountof substancesliberatedat therespectiveelectrodes are directlyproportionalto theirelectrochemicalequivalents. When Q coulombchargeis passedthroughthe electrolytyiccellsthe masses of silver,zinc and copperdepositedat therespectiveelectrodesbe ` m_(Ag)m_(ZN) and m_(cu)` RESPECTIVELY . ACCORDINGTO Faraday's second Law, ` m_(Ag) PROP Z_(Ag) m_(Zn) and m_(Cu) prop Z_(Cu)` or ` (M_(Ag))/(Z_(Ag)) = ( M_(Zn))/(Z_(Zn)) = (M_(Cu))/(Z_(Cu))` |
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