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State Bohr's quantisaiton condition of angularmomentum . Calculate theshortest wavelenghtof the Bracket series and state to whichpart ofthe electromagnetic spectrumdoes it belong . |
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Answer» Solution :For ELECTRON revolvingin astationaryorbit Bohr.squantisationcondiiton statethatthe angularmomentumis an integermultiple of `(H)/(2pi)` , wheren = 1,2,3………… The shortestwavelenghtof the Bracket series of hydrogenspectrumis given as : `(1)/(lambda) = R [(1)/((4)^(2)) - (1)/((OO)^(2))] =(R)/(16) =(1.097 xx 10^(7))/(16)` `RARR "" lambda = (16)/(1.097 xx 10^(7))= 14.59 xx 10^(7) m = 1459` nm Obviously thespectral linebelongto INFRA redregion of spectrum. |
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