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State and certify De-Morgan’s laws algebraically. |
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Answer» (i) X + X. Y = X L.H.S = X + X.Y = X.1 + X.Y = X(1 + Y) = X.1 = X = R.H.S (ii) X + X'.Y = X + Y L.H.S = X + X'.Y = (X + X').(X + Y) = 1.(X + Y) = X + Y = R.H.S |
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