Starting with the same initial conditions, an ideal gas expands from volume V_(1) to V_(2) in three different ways. The work done by the gas is W_(1) if the process is purely isothermal, W_(2) if purely isobaric and W_(3) is purely adiabatic. Then

Starting with the same initial conditions, an ideal gas expands from v

1.	Starting with the same initial conditions, an ideal gas expands from volume V_(1) to V_(2) in three different ways. The work done by the gas is W_(1) if the process is purely isothermal, W_(2) if purely isobaric and W_(3) is purely adiabatic. Then
Answer» `W_(2) GT W_(1) gt W_(3)` `W_(3) gt W_(1) gt W_(1)` `W_(1) gt W_(2) gt W_(3)` `W_(1) gt W_(3) gt W_(2)` Solution :THREE given PROCESSES are shown in the P-V GRAPHS. As work done by the gas = area under the P-V graph `because ("Area")_(2) gt ("Area")_(1) gt ("Area")_(3)` `:. W_(2) gt W_(1) gt W_(3)`